How to using or operator in typeorm?

In TypeORM, when constructing a query and you wish to combine multiple conditions using the 'OR' operator, you can utilize various methods of the Where clause to achieve this. Here are several approaches to implementing the 'OR' operator:

Using the Where Object

You can employ the orWhere method with queries built using the Where object, as illustrated below:

typescript
import { getRepository } from 'typeorm';
import { User } from './entity/User';

const userRepository = getRepository(User);

userRepository
  .createQueryBuilder('user')
  .where('user.firstName = :firstName', { firstName: 'John' })
  .orWhere('user.lastName = :lastName', { lastName: 'Doe' })
  .getMany();

In this example, we first filter based on user.firstName, then add another condition using orWhere for user.lastName. These conditions are combined using the 'OR' operator.

Using the find Method with FindOptions

When utilizing TypeORM's find method, you can pass a FindOptions object and specify the where property as an array of conditions. TypeORM will combine them using 'OR':

typescript
import { getRepository } from 'typeorm';
import { User } from './entity/User';

const userRepository = getRepository(User);

userRepository.find({
  where: [
    { firstName: 'John' },
    { lastName: 'Doe' }
  ]
});

Here, the where property accepts an array of conditions, with each object representing a distinct condition. TypeORM combines these conditions using 'OR' logic.

Using the Brackets Object

The Brackets object enables the creation of more complex 'OR' queries, allowing nested query conditions, as shown:

typescript
import { getRepository, Brackets } from 'typeorm';
import { User } from './entity/User';

const userRepository = getRepository(User);

userRepository
  .createQueryBuilder('user')
  .where(new Brackets(qb => {
    qb.where('user.firstName = :firstName', { firstName: 'John' })
      .orWhere('user.lastName = :lastName', { lastName: 'Doe' })
  }))
  .getMany();

In this example, using the Brackets object creates a nested query condition, providing greater flexibility for complex queries.

In summary, TypeORM offers multiple methods for using the 'OR' operator. Select the appropriate approach based on query complexity and your preference. In practice, choose between the orWhere method, the find method combined with FindOptions, or the Brackets object to construct more sophisticated query logic as needed.

In TypeScript, you can use various methods to dynamically assign properties to objects. Here are several different methods:

Method 1: Using index signatures

If you know the types of the properties in advance but not their names, you can use index signatures to define an object that can accept properties with arbitrary names.

typescript
// Define an index type
interface DynamicObject {
  [key: string]: any; // Can use string, number, symbol
}

// Create a dynamic object
const obj: DynamicObject = {};

// Dynamically add properties
obj['newProperty'] = 'New Value';
obj.dynamicField = 123;

console.log(obj);

Method 2: Using generics and keyof

If you have a specific object type and want to add or modify properties of that type, you can use generics and keyof.

typescript
type KnownObject = {
  existingProperty: string;
};

function setProperty<T, K extends keyof any, V>(
  obj: T,
  key: K,
  value: V
): T & Record<K, V> {
  return {
    ...obj,
    [key]: value,
  };
}

const knownObj: KnownObject = { existingProperty: 'Hello' };

const updatedObj = setProperty(knownObj, 'dynamicProperty', 456);

console.log(updatedObj);

Method 3: Using Object.assign()

The Object.assign() method copies all enumerable own properties from one or more source objects to a target object and returns the target object.

typescript
const obj: {[key: string]: any} = {};

Object.assign(obj, { dynamicProperty: 'Dynamic' });

console.log(obj);

Method 4: Using the spread operator (Spread Operator)

The spread operator copies properties from an existing object to a new object and adds new properties.

typescript
const obj = {};

const newProperty = 'dynamic';
const newObj = {
  ...obj,
  [newProperty]: 'Value',
};

console.log(newObj);

Summary

The above are several methods for dynamically assigning properties to objects in TypeScript. When using them in practice, choose the appropriate method based on your specific needs. Using index signatures and Object.assign() is usually more flexible, while using generics and keyof provides stronger type safety.

To use the OR operator with a sub-clause, you must duplicate the main-clause.

typescript
userRepository.find({
  where: [
    {
      firstName: 'Timber',
      lastName: 'Saw',
      project: {
        name: 'TypeORM',
      },
    },
    {
      firstName: 'Timber',
      lastName: 'Saw',
      project: {
        initials: 'TORM',
      },
    },
  ],
});

Find all Timber Saw with name = "TypeORM" or initials = "TORM".

You can combine the 'OR' operator with 'AND' conditions by executing the following.

javascript
db.getRepository(MyModel).find({
  where: [
      { name: "john", lastName: "doe" },
      { age: 20 }
  ]
})

The resulting SQL query is as follows:

sql
select * from model where (name = "john" and lastname = "doe") OR age = 20