How can I get part of url in Cypress

Within Cypress, you can retrieve the current page's URL using the cy.url() command. This command fetches the URL of the currently tested page and returns a Promise, which can be utilized for subsequent chained operations or assertions. Here's an example of using cy.url():

javascript
describe('URL Test', () => {
  it('should check the current URL', () => {
    // Navigate to a website
    cy.visit('https://example.com');

    // Retrieve the current URL and verify it contains a specific path
    cy.url().should('include', '/somePath');

    // You can also use `then()` to retrieve the URL value and perform more complex operations
    cy.url().then((currentUrl) => {
      // You can use the `currentUrl` variable to perform actions
      // For example, log the current URL
      console.log('The current URL is:', currentUrl);
    });
  });
});

In the above example, the cy.visit command navigates to the specified website, and then we retrieve the current page's URL using cy.url(). Using .should('include', '/somePath') ensures that the retrieved URL contains a specific path segment. If you need to perform more complex logic on the retrieved URL, you can use the .then() method to handle the currentUrl variable within a callback function. In this manner, Cypress provides a simple yet powerful way to interact with web pages during testing and can be easily combined with other Cypress commands to create complex test cases.